问题分析

高手过招，胜负只在毫厘之间
用科学的方法分析体育竞技比赛
输入：球员水平
输出：可预测的比赛成绩

比赛规则：

设计程序总体框架

代码

from random import random
def printIntro():print("这个程序模拟两个选手A和B的某种竞技比赛")print("程序运行需要A和B的能力值（以0-1之间的小数表示）")
def getInputs():a = eval(input("请输入选手A的能力值："))b = eval(input("请输入选手B的能力值："))n = eval(input("模拟比赛的场次："))return a, b, n
def printSummary(winsA, winsB):n = winsA + winsBprint("竞技分析开始，共模拟{}场比赛".format(n))print("选手A获胜{}场比赛，占比{:0.1%}".format(winsA, winsA / n))print("选手B获胜{}场比赛，占比{:0.1%}".format(winsB, winsB / n))
def gameover(a, b):return a == 15 or b == 15
def simOneGame(probA, probB):scoreA, scoreB = 0, 0serving = "A"while not gameover(scoreA, scoreB):if serving == "A":if random() < probA:scoreA += 1else:serving = "B"else:if random() < probB:scoreB += 1else:serving = "A"return scoreA, scoreB
def simNGames(n, probA, probB):winsA, winsB = 0, 0for i in range(n):scoreA, scoreB = simOneGame(probA, probB)if scoreA > scoreB:winsA += 1else:winsB += 1return winsA, winsB
def main():printIntro()probA, probB, n = getInputs()winsA, winsB = simNGames(n, probA, probB)printSummary(winsA,winsB)
main()

运行结果