递归返回想要的值

    /*** 递归数组返回想要的值，返回所有匹配到的节点组成的数组* @param {Array}           list        要递归的数组* @param {String}          childKey    子集字段* @param {String}          key         要匹配的字段（===判断）* @param {String/Number}   val         要匹配字段所对应的值（===判断）*/function getNode(list, childKey, key, val, result = []) {list.forEach(item => {if (item[key] === val) {result.push(item);}if (item[childKey] && item[childKey].length > 0) {getNode(item[childKey], childKey, key, val, result)}});return result};

例子：

    let tree = [{name: '水果',type: 'group',id: 1,children: [{name: '热带水果',type: 'group',id: 11,children: [{name: '香蕉',type: 'goods',id: 111,},{name: '菠萝',type: 'goods',id: 112,},{name: '榴莲',type: 'goods',id: 113,}]},{name: '温带水果',type: 'group',id: 12,children: [{name: '苹果',type: 'goods',id: 121,},{name: '西瓜',type: 'goods',id: 122,}]}]},{name: '粮食',type: 'group',id: 2,children: [{name: '温带作物',type: 'group',id: 21,children: [{name: '小麦',type: 'goods',id: 211,children: [{name: '黑小麦',type: 'goods',id: 2111},{name: '白小麦',type: 'goods',id: 2112}]}]}]}];let a = getNode(tree, 'children', 'type', 'goods')let c = getNode(tree, 'children', 'id', 2111 )

输出结果：