Java实现牛顿法和弦截法

写个数值分析作业用计算器算起来太麻烦咯，还是写些代码自动化一下

package test;public class mathHomework
{public static void main(String[] args){double x0 = 0.5, x1 = 0.6;newtonInteration(0.5,10);xianjieInteration(0.5,0.6,10);}/*** 	函数表达式* @param x* @return*/public static double func(double x){return x - Math.pow(Math.E, -x);}/*** 	导数表达式* @param x* @return*/public static double diffFunc(double x){return 1+Math.pow(Math.E, -x);}/*** 	 牛顿迭代法* @param x0* @param times*/public static void newtonInteration(double x0, int times){double xi=x0;double xi1;System.out.println("---------------------牛顿迭代法------------------------");for (int i = 0; i < times; i++){xi1=xi-func(xi)/diffFunc(xi);System.out.println("x"+(i+1)+"="+xi1);xi=xi1;}}/*** 	弦截法* @param x0* @param x1* @param times*/public static void xianjieInteration(double x0, double x1, int times){double xi=x0;double xi1=x1;double xi2;System.out.println("---------------------弦截法------------------------");for (int i = 0; i < times; i++){xi2 = (xi1 - (xi1 - xi) * func(xi1) / (func(xi1) - func(xi)));System.out.println("x"+(i+2)+"="+xi2);xi=xi1;xi1=xi2;}}}}

输出结果：

---------------------牛顿迭代法------------------------
x1=0.5663110031972182
x2=0.5671431650348623
x3=0.5671432904097811
x4=0.567143290409784
x5=0.5671432904097838
x6=0.567143290409784
x7=0.5671432904097838
x8=0.567143290409784
x9=0.5671432904097838
x10=0.567143290409784
---------------------弦截法------------------------
x2=0.5675445848373014
x3=0.5671409166735748
x4=0.5671432905821386
x5=0.567143290409784
x6=0.5671432904097838
x7=0.567143290409784
x8=0.567143290409784
x9=NaN
x10=NaN
x11=NaN