题目

分析

分析： 定义两个vector容器分别存储操作数和操作符，然后进行四则运算即可。

源码

#include <iostream>
#include <vector>
#include <cstdio>
using namespace std;
int main()
{int n;cin >> n;for (int i = 0; i < n; ++i){string a;cin >> a;vector<int>num;vector<char>opt;for (int j = 0; j < 7; ++j){if (a[j] >= '0' && a[j] <= '9'){int ans = a[j] - '0';num.push_back(ans);}else if (a[j] == 'x'){int xm = num[num.size() - 1] * (a[j + 1] - '0');num.pop_back();num.push_back(xm);j++;}else if (a[j] == '/'){int ym = num[num.size() - 1] / (a[j + 1] - '0');num.pop_back();num.push_back(ym);j++;}else if (a[j] == '+'){opt.push_back(a[j]);}else if (a[j] == '-'){opt.push_back(a[j]);}}int sum = num[0];for (int j = 0; j < opt.size(); ++j){if (opt[j] == '+'){sum += num[j + 1];}else{sum -= num[j + 1];}}if (sum == 24){cout << "Yes" << endl;}else{cout << "No" << endl;}}return 0;
}