饼块游戏的介绍

饼块游戏其实是一个我自创的一个小游戏，用户在程序运行后按下‘p’键即可开始游戏，游戏计时根据程序绘制出来的饼块数量的多少来决定。效果图如下：

此游戏将会用到四个不同的库——sys（提供与解释器交互的函数集合库）、math（许多关于数学的函数模块的集合库）、time（提供关于时间的测量的应用的函数集合库）与 pygame（用以写游戏的python模块集合库）

目录

饼块游戏的介绍

1.Pygame的下载（已下载可跳过）

2.Pygame,sys,math,time的导入及初始设置

3.while循环的设置

4.绘制圆

5.绘制线段

6.合并

7.源代码

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1.Pygame的下载（已下载可跳过）

Windows徽标键+R，会弹出一个运行框，输入‘cmd’，回车，输入‘pip install pygame’

如果要检查是否已经安装pygame，按下Windows徽标键+R，在运行框内输入‘cmd’，回车，输入‘python’，回车后再输入‘import pygame’，弹出版本号即已安装。

2.Pygame,sys,math,time的导入及初始设置

####查####
import pygame,sys,math,time
pygame.init()#初始化
sn = pygame.display.set_mode((600,500))#定义窗口大小
mt = pygame.font.Font(None,60)#(字体，大小)
pygame.display.set_caption('饼块游戏')

为了以防程序报错，我在导入时使用的是import（使用from···import···在后期循环内会报错，详见后文）。然后使用display.set_mode((,))去自定义窗口的大小，再用font.Font(,)去自定义字体与其大小，以便于后期直接调用这种自定义字体，最后还用到了display.set_caption('')来设置左上角标题。

3.while循环的设置

while 1:for event in pygame.event.get():#重复遍历用户输入键的值if event.type in (pygame.QUIT,pygame.KEYDOWN):#检测用户是否点击窗口右上角的关闭或者按下任何的键sys.exit()#结束程序运行pygame.display.update()#用来刷新屏幕进行显示

跟着if后面的这一串在后期需要改动（因为此游戏需要用到键盘）exit()是用来结束程序的一个函数，最后再添加上display.update()进行刷新显示，整个循环的进入，运作，退出的基本结构就出来了

ps:如果在导入时用from···import···报错结果如下：

我们能看到，程序可以进入循环阶段，但在运行时会报错（这时候就连偷懒都不容易了）。将程序改回： 

我们可以看到程序正常运行了。（ps:亲身试错过） 

4.绘制圆

pygame.draw.circle(sn,'black',(300,300),100,10)

这里分别设置了圆的颜色，位置（注：pygame的（0，0）在左上角），半径及其宽度，sn在这段程序外就设置了，这样是为了使其在打开的窗口内显示。

5.绘制线段

pygame.draw.line(sn,'black',(100,100),(400,450),8)

sn的作用跟圆的绘制时的作用一样，紧接着就是颜色，初始位置，结束位置，线条宽度。

 好啦，我们知道了这些，接下来就是对键盘的一顿敲击了

6.合并

首先让用户选择难度

print('请选择困难程度')
print('a为困难，b为中等，c为简单(点击键盘对应键键即可)')

初始化定义

import pygame,sys,math,time
pygame.init()
sn = pygame.display.set_mode((600,500))
mf = pygame.font.Font(None,60)
pygame.display.set_caption('饼块游戏')
a = b = c = d = e = f = g = h = a1 = b1 = c1 = d1 = e1 = f1 = a2 = b2 = c2 = d2 = 0
z = 1

我们创建一个while和for循环及其退出语句（按下e键退出在后文）

print('请选择困难程度')
print('a为困难，b为中等，c为简单(单击键盘此键即可)')
while 1:for event in pygame.event.get():#一定要加上此循环语句，否则下一句将会报错（先在for循环内调用）if event.type == pygame.QUIT:sys.exit()

接着便是判断用户选择的难度了，额外还要附加一个判断用户退出的一个判断

if event.type == pygame.KEYDOWN:if event.key == pygame.K_a:#（语句执行详见下文）elif event.key == pygame.K_b:#（语句执行详见下文）elif event.key == pygame.K_c:#（语句执行详见下文）elif event.key == pygame.K_e:print('您已选择退出游戏')time.sleep(0.7)sys.exit()

我们先开干困难关卡的程序，我们的a~h八个字符为0就是困难关卡中的八个按键，首先我们要先绘制出一个圆，再用线段去把圆分成8份，一份一个字母（或数字），用户按照任意顺序按下其中的键，被按到的那个字母（或数字）便会消失（就是以背景色为颜色在同样位置再写一遍既可达到效果）(a中的程序)

#困难模式的绘图
sn.fill('blue')
#绘制圆
pygame.draw.circle(sn,'black',(300,250),200,10)
#绘制线段
pygame.draw.line(sn,'black',(165,110),(420,400),14)#线段基本就复制粘贴既可
pygame.draw.line(sn,'black',(300,50),(300,450),10)
pygame.draw.line(sn,'black',(435,110),(180,400),14)
pygame.draw.line(sn,'black',(102,265),(498,265),10)
#添加运行文字
tm = mf.render('h',True,'red')#也是复制粘贴一波
sn.blit(tm,(170,200))
tm = mf.render('n',True,'red')
sn.blit(tm,(250,125))
tm = mf.render('8',True,'red')
sn.blit(tm,(170,300))
tm = mf.render('1',True,'red')
sn.blit(tm,(250,365))
tm = mf.render('l',True,'red')
sn.blit(tm,(350,125))
tm = mf.render('t',True,'red')
sn.blit(tm,(350,350))
tm = mf.render('z',True,'red')
sn.blit(tm,(430,200))
tm = mf.render('4',True,'red')
sn.blit(tm,(430,300))
pygame.display.update()
z = 2

紧接着判断用户按下p键开始游戏（当a执行后z=2既可执行以下语句，均与if event.key == pygame.K_a:同级）

if z == 2:if event.key == pygame.K_p:z = 2.5print('按下p键开始')

使得z为3后再执行下列循环（可能有人会问我，判断这么麻烦，咋不直接套娃一样一个一个往里套呢。啧，这是不行滴（亲身错误示范得知），会导致程序无法继续进行下一步）。在这就不得不说一个比较重要的函数——perf_counter()，这个函数开始时只要用time去调用它，结束时再调用一次就可得知“开始时间”和“结束时间”了（开始时非0，所以要相减）。最后一行必须将此上数字归零，否则就在下一次执行时由于满足直接进入此处（if a == b == c == d == e == f == g == h == 1:处）执行操作

if z == 2.5:st = time.perf_counter()z = 3
if z == 3:if event.key == pygame.K_h:a = 1tm = mf.render('h',True,'blue')sn.blit(tm,(170,200))if event.key == pygame.K_n:b = 1tm = mf.render('n',True,'blue')sn.blit(tm,(250,125))if event.key == pygame.K_8:c = 1tm = mf.render('8',True,'blue')sn.blit(tm,(170,300))if event.key == pygame.K_1:d = 1tm = mf.render('1',True,'blue')sn.blit(tm,(250,365))if event.key == pygame.K_l:e = 1tm = mf.render('l',True,'blue')sn.blit(tm,(350,125))if event.key == pygame.K_t:f = 1tm = mf.render('t',True,'blue')sn.blit(tm,(350,350))if event.key == pygame.K_z:g = 1tm = mf.render('z',True,'blue')sn.blit(tm,(430,200))if event.key == pygame.K_4:h = 1tm = mf.render('4',True,'blue')sn.blit(tm,(430,300))pygame.display.update()
if a == b == c == d == e == f == g == h == 1:ed = time.perf_counter()if ed - st > 5:print('挑战失败')sys.exit()
else:print('挑战成功')print('a为困难，b为中等，c为简单(单击键盘此键即可)')a = b = c = d = e = f = g = h = 0

中等难度的程序其实就简单些，大部分就是复制，还有一些修改就行了，和a部分差不多，就是少了一些字母

sn.fill('blue')
pygame.draw.circle(sn,'black',(300,250),200,10)
pygame.draw.line(sn,'black',(102,265),(498,265),10)
pygame.draw.line(sn,'black',(165,110),(420,400),14)
pygame.draw.line(sn,'black',(435,110),(180,400),14)
tm = mf.render('q',True,'red')
sn.blit(tm,(170,200))
tm = mf.render('5',True,'red')
sn.blit(tm,(290,125))
tm = mf.render('9',True,'red')
sn.blit(tm,(170,300))
tm = mf.render('m',True,'red')
sn.blit(tm,(290,365))
tm = mf.render('g',True,'red')
sn.blit(tm,(430,200))
tm = mf.render('i',True,'red')
sn.blit(tm,(430,300))
pygame.display.update()
z = 4

以及其执行语句

if z == 4:if event.key == pygame.K_p:z = 4.5print('按下p键开始')
if z == 4.5:st1 = time.perf_counter()z = 5
if z == 5:if event.key == pygame.K_q:a1 = 1tm = mf.render('q',True,'blue')sn.blit(tm,(170,200))if event.key == pygame.K_5:b1 = 1tm = mf.render('5',True,'blue')sn.blit(tm,(290,125))if event.key == pygame.K_9:c1 = 1tm = mf.render('9',True,'blue')sn.blit(tm,(170,300))if event.key == pygame.K_m:d1 = 1tm = mf.render('m',True,'blue')sn.blit(tm,(290,365))if event.key == pygame.K_g:e1 = 1tm = mf.render('g',True,'blue')sn.blit(tm,(430,200))if event.key == pygame.K_i:f1 = 1tm = mf.render('i',True,'blue')sn.blit(tm,(430,300))pygame.display.update()
if a1 == b1 == c1 == d1 == e1 == f1 == 1:ed1 = time.perf_counter()if ed1 - st1 > 4.5:print('挑战失败')sys.exit()else:print('挑战成功')print('a为困难，b为中等，c为简单(单击键盘此键即可)')a1 = b1 = c1 = d1 = e1 = f1 = 0

最后简单的那部分也没啥难的了，直接上代码吧！

sn.fill('blue')
pygame.draw.circle(sn,'black',(300,250),200,10)
pygame.draw.line(sn,'black',(300,50),(300,450),10)
pygame.draw.line(sn,'black',(102,265),(498,265),10)
tm = mf.render('d',True,'red')
sn.blit(tm,(200,150))
tm = mf.render('h',True,'red')
sn.blit(tm,(390,150))
tm = mf.render('0',True,'red')
sn.blit(tm,(200,350))
tm = mf.render('3',True,'red')
sn.blit(tm,(390,350))
pygame.display.update()
z = 6

if z == 6:if event.key == pygame.K_p:z = 6.5print('按下p键开始')
if z == 6.5:st2 = time.perf_counter()z = 7
if z == 7:if event.key == pygame.K_d:a2 = 1tm = mf.render('d',True,'blue')sn.blit(tm,(200,150))if event.key == pygame.K_h:b2 = 1tm = mf.render('h',True,'blue')sn.blit(tm,(390,150))if event.key == pygame.K_0:c2 = 1tm = mf.render('0',True,'blue')sn.blit(tm,(200,350))if event.key == pygame.K_3:d2 = 1tm = mf.render('3',True,'blue')sn.blit(tm,(390,350))pygame.display.update()
if a2 == b2 == c2 == d2 == 1:ed2 = time.perf_counter()if ed2 - st2 > 2.5:print('挑战失败')sys.exit()else:print('挑战成功')print('a为困难，b为中等，c为简单(单击键盘此键即可)')a2 = b2 = c2 = d2 = 0

7.源代码

最后在此献上源代码：

import pygame,sys,math,time
pygame.init()
sn = pygame.display.set_mode((600,500))
mf = pygame.font.Font(None,50)
pygame.display.set_caption('饼块游戏')
a = b = c = d = e = f = g = h = a1 = b1 = c1 = d1 = e1 = f1 = a2 = b2 = c2 = d2 = 0
print('请选择困难程度')
print('a为困难，b为中等，c为简单(单击键盘此键即可)')
print('按下e退出')
z = 1
while 1:for event in pygame.event.get():if event.type == pygame.QUIT:sys.exit()if event.type == pygame.KEYDOWN:if event.key == pygame.K_a:sn.fill('blue')pygame.draw.circle(sn,'black',(300,250),200,10)pygame.draw.line(sn,'black',(165,110),(420,400),14)pygame.draw.line(sn,'black',(300,50),(300,450),10)pygame.draw.line(sn,'black',(435,110),(180,400),14)pygame.draw.line(sn,'black',(102,265),(498,265),10)tm = mf.render('h',True,'red')sn.blit(tm,(170,200))tm = mf.render('n',True,'red')sn.blit(tm,(250,125))tm = mf.render('8',True,'red')sn.blit(tm,(170,300))tm = mf.render('1',True,'red')sn.blit(tm,(250,365))tm = mf.render('l',True,'red')sn.blit(tm,(350,125))tm = mf.render('t',True,'red')sn.blit(tm,(350,350))tm = mf.render('z',True,'red')sn.blit(tm,(430,200))tm = mf.render('4',True,'red')sn.blit(tm,(430,300))pygame.display.update()z = 2elif event.key == pygame.K_b:sn.fill('blue')pygame.draw.circle(sn,'black',(300,250),200,10)pygame.draw.line(sn,'black',(102,265),(498,265),10)pygame.draw.line(sn,'black',(165,110),(420,400),14)pygame.draw.line(sn,'black',(435,110),(180,400),14)tm = mf.render('q',True,'red')sn.blit(tm,(170,200))tm = mf.render('5',True,'red')sn.blit(tm,(290,125))tm = mf.render('9',True,'red')sn.blit(tm,(170,300))tm = mf.render('m',True,'red')sn.blit(tm,(290,365))tm = mf.render('g',True,'red')sn.blit(tm,(430,200))tm = mf.render('i',True,'red')sn.blit(tm,(430,300))pygame.display.update()z = 4elif event.key == pygame.K_c:sn.fill('blue')pygame.draw.circle(sn,'black',(300,250),200,10)pygame.draw.line(sn,'black',(300,50),(300,450),10)pygame.draw.line(sn,'black',(102,265),(498,265),10)tm = mf.render('d',True,'red')sn.blit(tm,(200,150))tm = mf.render('h',True,'red')sn.blit(tm,(390,150))tm = mf.render('0',True,'red')sn.blit(tm,(200,350))tm = mf.render('3',True,'red')sn.blit(tm,(390,350))pygame.display.update()z = 6elif event.key == pygame.K_e:print('您已选择退出游戏')time.sleep(0.7)sys.exit()if z == 2:if event.key == pygame.K_p:z = 2.5print('按下p键开始')if z == 2.5:st = time.perf_counter()z = 3if z == 3:if event.key == pygame.K_h:a = 1tm = mf.render('h',True,'blue')sn.blit(tm,(170,200))if event.key == pygame.K_n:b = 1tm = mf.render('n',True,'blue')sn.blit(tm,(250,125))if event.key == pygame.K_8:c = 1tm = mf.render('8',True,'blue')sn.blit(tm,(170,300))if event.key == pygame.K_1:d = 1tm = mf.render('1',True,'blue')sn.blit(tm,(250,365))if event.key == pygame.K_l:e = 1tm = mf.render('l',True,'blue')sn.blit(tm,(350,125))if event.key == pygame.K_t:f = 1tm = mf.render('t',True,'blue')sn.blit(tm,(350,350))if event.key == pygame.K_z:g = 1tm = mf.render('z',True,'blue')sn.blit(tm,(430,200))if event.key == pygame.K_4:h = 1tm = mf.render('4',True,'blue')sn.blit(tm,(430,300))pygame.display.update()if a == b == c == d == e == f == g == h == 1:ed = time.perf_counter()if ed - st > 6.5:print('挑战失败')sys.exit()else:print('挑战成功')print('a为困难，b为中等，c为简单(单击键盘此键即可)')a = b = c = d = e = f = g = h = 0if z == 4:if event.key == pygame.K_p:z = 4.5print('按下p键开始')if z == 4.5:st1 = time.perf_counter()z = 5if z == 5:if event.key == pygame.K_q:a1 = 1tm = mf.render('q',True,'blue')sn.blit(tm,(170,200))if event.key == pygame.K_5:b1 = 1tm = mf.render('5',True,'blue')sn.blit(tm,(290,125))if event.key == pygame.K_9:c1 = 1tm = mf.render('9',True,'blue')sn.blit(tm,(170,300))if event.key == pygame.K_m:d1 = 1tm = mf.render('m',True,'blue')sn.blit(tm,(290,365))if event.key == pygame.K_g:e1 = 1tm = mf.render('g',True,'blue')sn.blit(tm,(430,200))if event.key == pygame.K_i:f1 = 1tm = mf.render('i',True,'blue')sn.blit(tm,(430,300))pygame.display.update()if a1 == b1 == c1 == d1 == e1 == f1 == 1:ed1 = time.perf_counter()if ed1 - st1 > 4.5:print('挑战失败')sys.exit()else:print('挑战成功')print('a为困难，b为中等，c为简单(单击键盘此键即可)')a1 = b1 = c1 = d1 = e1 = f1 = 0if z == 6:if event.key == pygame.K_p:z = 6.5print('按下p键开始')if z == 6.5:st2 = time.perf_counter()z = 7if z == 7:if event.key == pygame.K_d:a2 = 1tm = mf.render('d',True,'blue')sn.blit(tm,(200,150))if event.key == pygame.K_h:b2 = 1tm = mf.render('h',True,'blue')sn.blit(tm,(390,150))if event.key == pygame.K_0:c2 = 1tm = mf.render('0',True,'blue')sn.blit(tm,(200,350))if event.key == pygame.K_3:d2 = 1tm = mf.render('3',True,'blue')sn.blit(tm,(390,350))pygame.display.update()if a2 == b2 == c2 == d2 == 1:ed2 = time.perf_counter()if ed2 - st2 > 2.5:print('挑战失败')sys.exit()else:print('挑战成功')print('a为困难，b为中等，c为简单(单击键盘此键即可)')a2 = b2 = c2 = d2 = 0

ps：有错请各位指出，还请各位多多包涵噢