洛谷AC的第一题！

主要卡点
（1）E之后的数据不能管，要break掉；
（2）当输或赢的数量大于等于11时（注意是大于等于！不是等于！），还要判断输赢大于等于2，才能输出剩余的（也就是当前正在比赛的）数据；

import java.util.ArrayList;
import java.util.Scanner;注意主类要改成Main，我想学C++了...tm题解全是C++！淦！java的题解一个都找不到！
public class Code01_PingPong {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);String str = null;int win = 0;int lose = 0;int i = 0;boolean findE = false;char[] chars = null;ArrayList<String> inputs = new ArrayList<>();while (scanner.hasNext()) {inputs.add(scanner.next());char[] chars1 = inputs.get(i).toCharArray();for (int j = 0; j < chars1.length; j++) {if (chars1[j] == 'E') {findE = true;break;}}if (findE) {break;}i++;}for (int j = 0; j < inputs.size(); j++) {chars = inputs.get(j).toCharArray();for (int p = 0; p < chars.length; p++) {if (chars[p] == 'W') {win++;} else if (chars[p] == 'L') {lose++;} else {System.out.println(win + ":" + lose);break;}if ((lose >= 11 || win >= 11) && Math.abs(lose - win) >= 2) {System.out.println(win + ":" + lose);win = 0;lose = 0;}}}win = 0;lose = 0;System.out.println();for (int j = 0; j < inputs.size(); j++) {chars = inputs.get(j).toCharArray();for (int p = 0; p < chars.length; p++) {if (chars[p] == 'W') {win++;} else if (chars[p] == 'L') {lose++;} else {System.out.println(win + ":" + lose);break;}if ((lose >= 21 || win >= 21) && Math.abs(lose - win) >= 2) {System.out.println(win + ":" + lose);win = 0;lose = 0;}}}}}