下载好后直接用ida就可以打开，找到main函数 

_int64 __fastcall main(__int64 a1, char **a2, char **a3)
{__int64 result; // rax__int64 v4; // [rsp+0h] [rbp-40h]char v5; // [rsp+9h] [rbp-37h]char s2[4]; // [rsp+Ah] [rbp-36h]char s[40]; // [rsp+10h] [rbp-30h]unsigned __int64 v8; // [rsp+38h] [rbp-8h]v8 = __readfsqword(0x28u);memset(s, 0, 0x19uLL);printf("Tell me the flag:", 0LL);scanf("%s", s);strcpy(s2, "actf{");LODWORD(v4) = 0;while ( (signed int)v4 <= 4 )                 // v4为8字节，低4位存储索引，高四位存储值{*((_BYTE *)&v4 + (signed int)v4 + 4) = s[(signed int)v4];LODWORD(v4) = v4 + 1;}v5 = 0;if ( !strcmp((const char *)&v4 + 4, s2) )     // 比较flag头{if ( (unsigned __int8)sub_78A((__int64)s) )printf("That's True Flag!", s2, v4);elseprintf("don't stop trying...", s2, v4);result = 0LL;}

通过这些代码，我们知道flag的头为actf{

进入到主要的函数分析sub_78A

while ( byte_201020[v2] !=0x21 ){v2 -= v4;                                   // 当前坐标// 减去上次移动多移动的一次if ( *(_BYTE *)(v3 + a1) != 87 || v4 == -16 ){if ( *(_BYTE *)(v3 + a1) != 69 || v4 == 1 ){if ( *(_BYTE *)(v3 + a1) != 77 || v4 == 16 ){if ( *(_BYTE *)(v3 + a1) != 74 || v4 == -1 )return 0LL;                         // 判断最后一位是否为'}'// v4 = -1;                              // a1[v3]='J'向左移动}else{v4 = 16;                              // a1[v3]='M'向下}}else{v4 = 1;                                 // a1[v3]='E'向右}}else{v4 = -16;                                 // a1[v3]='W'向上移动}

这个函数其实就是一个迷宫，16*16，这个迷宫并不是很复杂可以直接手动写

向下移动：M
向左移动：J
向上移动：E
向右移动：W

00 00 00 00 23 00 00 00 00 00 00 00 23 23 23 23
00 00 00 23 23 00 00 00 4F 4F 00 00 00 00 00 00
00 00 00 00 00 00 00 00 4F 4F 00 50 50 00 00 00
00 00 00 4C 00 4F 4F 00 4F 4F 00 50 50 00 00 00
00 00 00 4C 00 4F 4F 00 4F 4F 00 50 00 00 00 00
00 00 4C 4C 00 4F 4F 00 00 00 00 50 00 00 00 00
00 00 00 00 00 4F 4F 00 00 00 00 50 00 00 00 00
23 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 23 00 00 00
00 00 00 00 00 00 4D 4D 4D 00 00 00 23 00 00 00
00 00 00 00 00 00 00 4D 4D 4D 00 00 00 00 45 45
00 00 00 30 00 4D 00 4D 00 4D 00 00 00 00 45 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 45 45
54 54 54 49 00 4D 00 4D 00 4D 00 00 00 00 45 00
00 54 00 49 00 4D 00 4D 00 4D 00 00 00 00 45 00
00 54 00 49 00 4D 00 4D 00 4D 21 00 00 00 45 45

外层while循环，就是到0x21时停止，v2为当前位置，v3从输入的第六个字符开始遍历数组，v4实际是对v2位置的移动。

第二处，用了个循环，if条件判断的是位置是否到达边界，越界退出

整个迷宫就是用WEMJ控制移动，0可以移动（一直移动），到达非0位置停止，返回上一位置。左上角为起点，0x21为终点。手动解迷宫

别人写的脚本：

#include <stdio.h>
char maze[256] = {0x00, 0x00, 0x00, 0x00, 0x23, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x23, 0x23, 0x23, 0x23,0x00, 0x00, 0x00, 0x23, 0x23, 0x00, 0x00, 0x00, 0x4F, 0x4F, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x4F, 0x4F, 0x00, 0x50, 0x50, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x4C, 0x00, 0x4F, 0x4F, 0x00, 0x4F, 0x4F, 0x00, 0x50, 0x50, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x4C, 0x00, 0x4F, 0x4F, 0x00, 0x4F, 0x4F, 0x00, 0x50, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x4C, 0x4C, 0x00, 0x4F, 0x4F, 0x00, 0x00, 0x00, 0x00, 0x50, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x4F, 0x4F, 0x00, 0x00, 0x00, 0x00, 0x50, 0x00, 0x00, 0x00, 0x00,0x23, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x23, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x4D, 0x4D, 0x4D, 0x00, 0x00, 0x00, 0x23, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x4D, 0x4D, 0x4D, 0x00, 0x00, 0x00, 0x00, 0x45, 0x45,0x00, 0x00, 0x00, 0x30, 0x00, 0x4D, 0x00, 0x4D, 0x00, 0x4D, 0x00, 0x00, 0x00, 0x00, 0x45, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x45, 0x45,0x54, 0x54, 0x54, 0x49, 0x00, 0x4D, 0x00, 0x4D, 0x00, 0x4D, 0x00, 0x00, 0x00, 0x00, 0x45, 0x00,0x00, 0x54, 0x00, 0x49, 0x00, 0x4D, 0x00, 0x4D, 0x00, 0x4D, 0x00, 0x00, 0x00, 0x00, 0x45, 0x00,0x00, 0x54, 0x00, 0x49, 0x00, 0x4D, 0x00, 0x4D, 0x00, 0x4D, 0x21, 0x00, 0x00, 0x00, 0x45, 0x45
};
int main(void)
{int i, j;for (i = 0; i < 16; i++){for (j = 0; j < 16; j++){if (i == 0 && j == 0)printf("☆");  //起点else if (maze[16 * i + j] == 0)printf("□");  //路else if (maze[16 * i + j] == 0x21)printf("★");  //终点else printf("■"); //障碍物}putchar('\n');}
}

 flag{MEWEMEWJMEWJM}