写了一个看了虎躯一震的代码
题目为：

【if 语句】从键盘上输入一个不多于 5 位的正整数，编写程序实现如下要求：

（1）求出它是几位数；
（2）分别输出每一位数字；
（3）按逆序输出每位数字，例如原数为 321，应输出 123。

下面贴上源代码（python）

import mathnumber=int(input("请输入一个不多于5位的正整数："))
digit=0;
number_1=0
number_2=0
number_3=0
number_4=0
number_5=0
if number>=10000:digit=5number_5=math.floor(number/10000)number_4=math.floor(number/1000)-number_5*10number_3=math.floor(number/100)-number_5*100-number_4*10number_2=math.floor(number/10)-number_5*1000-number_4*100-number_3*10number_1=math.floor(number/1)-number_5*10000-number_4*1000-number_3*100-number_2*10
elif number>=1000:digit=4number_4=math.floor(number/1000)number_3=math.floor(number/100)-number_4*10number_2=math.floor(number/10)-number_4*100-number_3*10number_1=math.floor(number/1)-number_4*1000-number_3*100-number_2*10
elif number>=100:digit=3number_3=math.floor(number/100)number_2=math.floor(number/10)-number_3*10number_1=math.floor(number/1)-number_3*100-number_2*10
elif number>=10:digit=2number_2=math.floor(number/10)number_1=math.floor(number/1)-number_2*10
elif number>=0:digit=1number_1=math.floor(number/1)print(str(number)+"是一个"+str(digit)+"位数")if number_5!=0:print("万位数字为："+str(number_5))
if number_4!=0:print("千位数字为："+str(number_4))
if number_3!=0:print("百位数字为："+str(number_3))
if number_2!=0:print("十位数字为："+str(number_2))
if number_1!=0:print("个位数字为："+str(number_1))print("逆序输出为：")
if digit==1:print(str(number_1))
elif digit==2:print(str(number_1)+str(number_2))
elif digit==3:print(str(number_1)+str(number_2)+str(number_3))
elif digit==4:print(str(number_1)+str(number_2)+str(number_3)+str(number_4))
elif digit==5:print(str(number_1)+str(number_2)+str(number_3)+str(number_4)+str(number_5))

运行结果当然也相当的nice: