#include<iostream>
using namespace std;
const int N = 1e5 + 10;
int a[N], b[N];
int main(){//时间复杂度是o(n)，双指针算法int n, m,num = 0;cin >> n >> m;for(int i = 0; i < n; i ++) cin >> a[i];for(int i = 0; i < m; i ++) cin >> b[i];int i = 0, j = 0;while (i < n && j < m){if (a[i] == b[j]){i ++;j ++;}else j ++;}if (i != n )cout << "No";else cout << "Yes";
}