SQL架构

表1: Person
+-------------+---------+
| 列名         | 类型     |
+-------------+---------+
| PersonId    | int     |
| FirstName   | varchar |
| LastName    | varchar |
+-------------+---------+
PersonId 是上表主键

表2: Address
+-------------+---------+
| 列名         | 类型    |
+-------------+---------+
| AddressId   | int     |
| PersonId    | int     |
| City        | varchar |
| State       | varchar |
+-------------+---------+
AddressId 是上表主键

编写一个 SQL 查询，满足条件：无论 person 是否有地址信息，都需要基于上述两表提供 person 的以下信息：
FirstName, LastName, City, State

先开启本地mysql服务 

使用数据库test，新建两个表person和address，并向两数据表中添加数据

SET NAMES utf8mb4;
SET FOREIGN_KEY_CHECKS = 0;-- ----------------------------
-- Table structure for person
-- ----------------------------
DROP TABLE IF EXISTS `person`;
CREATE TABLE `person`  (`PersonId` int(11) NOT NULL,`FirstName` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci NULL DEFAULT NULL,`LastName` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci NULL DEFAULT NULL,PRIMARY KEY (`PersonId`) USING BTREE
) ENGINE = InnoDB CHARACTER SET = latin1 COLLATE = latin1_swedish_ci ROW_FORMAT = Compact;-- ----------------------------
-- Records of person
-- ----------------------------
INSERT INTO `person` VALUES (100001, '张', '三');
INSERT INTO `person` VALUES (100002, '李', '四');
INSERT INTO `person` VALUES (100003, '王', '五');
INSERT INTO `person` VALUES (100004, '马', '六');
INSERT INTO `person` VALUES (100005, '陈', '七');SET FOREIGN_KEY_CHECKS = 1;

SET NAMES utf8mb4;
SET FOREIGN_KEY_CHECKS = 0;-- ----------------------------
-- Table structure for address
-- ----------------------------
DROP TABLE IF EXISTS `address`;
CREATE TABLE `address`  (`AddressId` int(11) NOT NULL,`PersonId` int(11) NULL DEFAULT NULL,`City` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci NULL DEFAULT NULL,`State` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci NULL DEFAULT NULL,PRIMARY KEY (`AddressId`) USING BTREE
) ENGINE = InnoDB CHARACTER SET = latin1 COLLATE = latin1_swedish_ci ROW_FORMAT = Compact;-- ----------------------------
-- Records of address
-- ----------------------------
INSERT INTO `address` VALUES (200001, 100003, '北京', '1');
INSERT INTO `address` VALUES (200002, 100005, '上海', '0');
INSERT INTO `address` VALUES (200003, 100002, '杭州', '1');
INSERT INTO `address` VALUES (200004, 100004, '深圳', '0');
INSERT INTO `address` VALUES (200005, 100001, '广州', '1');SET FOREIGN_KEY_CHECKS = 1;

题目要求：

编写一个 SQL 查询，满足条件：

无论 person 是否有地址信息，

都需要基于上述两表提供 person 的以下信息：FirstName, LastName, City, State

SELECTFirstName,LastName,City,State 
FROMperson pLEFT JOIN address a ON p.PersonId = a.PersonId

SELECTFirstName,LastName,City,State 
FROMperson pINNER JOIN address a ON p.PersonId = a.PersonId

SELECTFirstName,LastName,City,State 
FROMperson pRIGHT JOIN address a ON p.PersonId = a.PersonId

1. INNER JOIN：内连接，如果表中有至少一个匹配，则返回行

2. LEFT JOIN：左连接，即使右表中没有匹配，也从左表返回所有的行

3. RIGHT JOIN：右连接，即使左表中没有匹配，也从右表返回所有的行