#include <bits/stdc++.h>using namespace std;
#define IOS ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);void split(string s, vector<string> &v, string c)//分割字符串
{size_t pos1, pos2;pos2 = s.find(c);pos1 = 0;while (string::npos != pos2){v.push_back(s.substr(pos1, pos2 - pos1));pos1 = pos2 + c.size();pos2 = s.find(c, pos1);}if (pos1 != s.length())v.push_back(s.substr(pos1));
}void solve2(string s, map<string, int> &m)//处理以加号为分割的块
{stringstream ss;ss << s[0];for (int i = 1; i < s.length(); i++){if (isdigit(s[i]) && !isdigit(s[i - 1]))ss << ' ';else if (isupper(s[i]))ss << ' ';else if (s[i] == '(' || s[i] == ')')ss << " ";ss << s[i];}string temp;vector<string> v;vector<pair<string, int>> element;vector<int> leftpar;while (ss >> temp)v.push_back(temp);int times = 1;if (isdigit(v[0][0]))times = stoi(v[0]);for (int i = isdigit(v[0][0]) ? 1 : 0; i < v.size(); i++){if (isupper(v[i][0])){if (i + 1 < v.size() && isdigit(v[i + 1][0])){int t = stoi(v[i + 1]);element.push_back({v[i], t});i++;}else{element.push_back({v[i], 1});}}else if (v[i] == "("){leftpar.push_back(element.size());}else if (v[i] == ")"){if (i + 1 < v.size() && isdigit(v[i + 1][0])){int st = leftpar.back();int t = stoi(v[i + 1]);leftpar.pop_back();for (int j = st; j < element.size(); j++){element[j].second *= t;}i++;}}}for (auto &x:element){m[x.first] += x.second * times;}
}void solve(string s, map<string, int> &m)//处理左边或右边
{vector<string> v;split(s, v, "+");for (int i = 0; i < v.size(); i++)solve2(v[i], m);
}bool equal(map<string, int> &m1, map<string, int> &m2)
{if (m1.size() != m2.size())return false;for (auto &x:m1){if (m2[x.first] != x.second)return false;}return true;
}int main()
{IOS;int n;cin >> n;for (int i = 1; i <= n; i++){string str;cin >> str;map<string, int> m1, m2;vector<string> part;split(str, part, "=");solve(part[0], m1);solve(part[1], m2);
//        cout<<"m1 :: ";
//        for (auto &x:m1)
//        {
//            cout << x.first << "[" << x.second << "] ";
//        }
//        cout << endl;
//        cout<<"m1 :: ";
//        for (auto &x:m2)
//        {
//            cout << x.first << "[" << x.second << "] ";
//        }
//        cout << endl;if (equal(m1, m2))cout << "Y" << endl;elsecout << "N" << endl;}return 0;
}