本文翻译自：What is this date format? 2011-08-12T20:17:46.384Z

I have the following date: 2011-08-12T20:17:46.384Z . 我有以下日期： 2011-08-12T20:17:46.384Z 。 What format is this? 这是什么格式？ I'm trying to parse it with Java 1.4 via DateFormat.getDateInstance().parse(dateStr) and I'm getting 我试图通过DateFormat.getDateInstance().parse(dateStr)用Java 1.4解析它，

java.text.ParseException: Unparseable date: "2011-08-12T20:17:46.384Z" java.text.ParseException：无法解析的日期：“ 2011-08-12T20：17：46.384Z”

I think I should be using SimpleDateFormat for parsing, but I have to know the format string first. 我想我应该使用SimpleDateFormat进行解析，但是我必须首先知道格式字符串。 All I have for that so far is yyyy-MM-dd , because I don't know what the T means in this string--something time zone-related? 到目前为止，我所拥有的只是yyyy-MM-dd ，因为我不知道T在此字符串中的含义是什么-与时区有关？ This date string is coming from the lcmis:downloadedOn tag shown on Files CMIS download history media type . 此日期字符串来自文件CMIS下载历史记录媒体类型上显示的lcmis:downloadedOn标记。

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#1楼

参考：https://stackoom.com/question/ZGXv/这个日期格式是什么-T-Z

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#2楼

tl;dr tl; dr

Standard ISO 8601 format is used by your input string. 输入字符串使用标准ISO 8601格式。

Instant.parse ( "2011-08-12T20:17:46.384Z" ) 

ISO 8601 ISO 8601

This format is defined by the sensible practical standard, ISO 8601 . 此格式由明智的实用标准ISO 8601定义 。

The T separates the date portion from the time-of-day portion. T将日期部分与时间部分分开。 The Z on the end means UTC (that is, an offset-from-UTC of zero hours-minutes-seconds). 末尾的Z表示UTC （即，相对于UTC的偏移量为零小时-分钟-秒）。 The Z is pronounced “Zulu” . Z 发音为“ Zulu” 。

java.time java.time

The old date-time classes bundled with the earliest versions of Java have proven to be poorly designed, confusing, and troublesome. 事实证明，与最早的Java版本捆绑在一起的旧的日期时间类设计不佳，令人困惑且麻烦。 Avoid them. 避免他们。

Instead, use the java.time framework built into Java 8 and later. 相反，请使用Java 8及更高版本中内置的java.time框架。 The java.time classes supplant both the old date-time classes and the highly successful Joda-Time library. java.time类取代了旧的日期时间类和非常成功的Joda-Time库。

The java.time classes use ISO 8601 by default when parsing/generating textual representations of date-time values. 解析/生成日期时间值的文本表示时，java.time类默认使用ISO 8601 。

The Instant class represents a moment on the timeline in UTC with a resolution of nanoseconds . Instant类表示UTC时间线上的时刻，分辨率为纳秒 。 That class can directly parse your input string without bothering to define a formatting pattern. 该类可以直接解析您的输入字符串，而无需费心定义格式设置模式。

Instant instant = Instant.parse ( "2011-08-12T20:17:46.384Z" ) ;

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About java.time 关于java.time

The java.time framework is built into Java 8 and later. java.time框架内置于Java 8及更高版本中。 These classes supplant the troublesome old legacy date-time classes such as java.util.Date , Calendar , & SimpleDateFormat . 这些类取代了麻烦的旧的旧式日期时间类，例如java.util.Date ， Calendar和SimpleDateFormat 。

The Joda-Time project, now in maintenance mode , advises migration to the java.time classes. 现在处于维护模式的Joda-Time项目建议迁移到java.time类。

To learn more, see the Oracle Tutorial . 要了解更多信息，请参见Oracle教程 。 And search Stack Overflow for many examples and explanations. 并在Stack Overflow中搜索许多示例和说明。 Specification is JSR 310 . 规格为JSR 310 。

Where to obtain the java.time classes? 在哪里获取java.time类？

• Java SE 8 , Java SE 9 , and later Java SE 8 ， Java SE 9和更高版本
  • Built-in. 内置的
  • Part of the standard Java API with a bundled implementation. 标准Java API的一部分，具有捆绑的实现。
  • Java 9 adds some minor features and fixes. Java 9添加了一些次要功能和修复。
• Java SE 6 and Java SE 7 Java SE 6和Java SE 7
  • Much of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport . java.time的许多功能在ThreeTen- Backport中都被反向移植到Java 6和7。
• Android 安卓系统
  • Later versions of Android bundle implementations of the java.time classes. 更高版本的Android捆绑了java.time类的实现。
  • For earlier Android, the ThreeTenABP project adapts ThreeTen-Backport (mentioned above). 对于较早的Android， ThreeTenABP项目改编了ThreeTen-Backport （如上所述）。 See How to use ThreeTenABP… . 请参阅如何使用ThreeTenABP… 。

The ThreeTen-Extra project extends java.time with additional classes. ThreeTen-Extra项目使用其他类扩展了java.time。 This project is a proving ground for possible future additions to java.time. 该项目为将来可能在java.time中添加内容提供了一个试验场。 You may find some useful classes here such as Interval , YearWeek , YearQuarter , and more . 您可以在这里找到一些有用的类，比如Interval ， YearWeek ， YearQuarter ，和更多 。

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#3楼

There are other ways to parse it rather than the first answer. 还有其他解析方法，而不是第一个答案。 To parse it: 要解析它：

(1) If you want to grab information about date and time, you can parse it to a ZonedDatetime (since Java 8 ) or Date (old) object: （1）如果要获取有关日期和时间的信息，则可以将其解析为ZonedDatetime （因为Java 8 ）或Date （旧）对象：

// ZonedDateTime's default format requires a zone ID(like [Australia/Sydney]) in the end.
// Here, we provide a format which can parse the string correctly.
DateTimeFormatter dtf = DateTimeFormatter.ISO_DATE_TIME;
ZonedDateTime zdt = ZonedDateTime.parse("2011-08-12T20:17:46.384Z", dtf);

or 要么

// 'T' is a literal.
// 'X' is ISO Zone Offset[like +01, -08]; For UTC, it is interpreted as 'Z'(Zero) literal.
String pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSX";// since no built-in format, we provides pattern directly.
DateFormat df = new SimpleDateFormat(pattern);Date myDate = df.parse("2011-08-12T20:17:46.384Z");

(2) If you don't care the date and time and just want to treat the information as a moment in nanoseconds, then you can use Instant : （2）如果您不在乎日期和时间，而只想将信息视为纳秒级的时间，则可以使用Instant ：

// The ISO format without zone ID is Instant's default.
// There is no need to pass any format.
Instant ins = Instant.parse("2011-08-12T20:17:46.384Z");

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#4楼

You can use the following example. 您可以使用以下示例。

    String date = "2011-08-12T20:17:46.384Z";String inputPattern = "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'";String outputPattern = "yyyy-MM-dd HH:mm:ss";LocalDateTime inputDate = null;String outputDate = null;DateTimeFormatter inputFormatter = DateTimeFormatter.ofPattern(inputPattern, Locale.ENGLISH);DateTimeFormatter outputFormatter = DateTimeFormatter.ofPattern(outputPattern, Locale.ENGLISH);inputDate = LocalDateTime.parse(date, inputFormatter);outputDate = outputFormatter.format(inputDate);System.out.println("inputDate: " + inputDate);System.out.println("outputDate: " + outputDate);

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#5楼

This technique translates java.util.Date to UTC format (or any other) and back again. 此技术将java.util.Date转换为UTC格式（或任何其他格式），然后再次返回。

Define a class like so: 像这样定义一个类：

import java.util.Date;import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;public class UtcUtility {public static DateTimeFormatter UTC = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'").withZoneUTC();public static Date parse(DateTimeFormatter dateTimeFormatter, String date) {return dateTimeFormatter.parseDateTime(date).toDate();
}public static String format(DateTimeFormatter dateTimeFormatter, Date date) {return format(dateTimeFormatter, date.getTime());
}private static String format(DateTimeFormatter dateTimeFormatter, long timeInMillis) {DateTime dateTime = new DateTime(timeInMillis);String formattedString = dateTimeFormatter.print(dateTime);return formattedString;
}

} }

Then use it like this: 然后像这样使用它：

Date date = format(UTC, "2020-04-19T00:30:07.000Z")

or 要么

String date = parse(UTC, new Date())

You can also define other date formats if you require (not just UTC) 如果需要，您还可以定义其他日期格式（不仅限于UTC）

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#6楼

@John-Skeet gave me the clue to fix my own issue around this. @ John-Skeet为我提供了解决此问题的线索。 As a younger programmer this small issue is easy to miss and hard to diagnose. 作为一个年轻的程序员，这个小问题很容易遗漏并且很难诊断。 So Im sharing it in the hopes it will help someone. 因此，我希望分享它，希望对您有所帮助。

My issue was that I wanted to parse the following string contraining a time stamp from a JSON I have no influence over and put it in more useful variables. 我的问题是我想解析下面的字符串，与来自我没有影响的JSON的时间戳形成鲜明对比，并将其放入更有用的变量中。 But I kept getting errors. 但是我不断出错。

So given the following (pay attention to the string parameter inside ofPattern(); 因此，给出以下内容（注意Pattern（）内的字符串参数；

String str = "20190927T182730.000Z"LocalDateTime fin;
fin = LocalDateTime.parse( str, DateTimeFormatter.ofPattern("yyyyMMdd'T'HHmmss.SSSZ") );

Error: 错误：

Exception in thread "main" java.time.format.DateTimeParseException: Text 
'20190927T182730.000Z' could not be parsed at index 19

The problem? 问题？ The Z at the end of the Pattern needs to be wrapped in 'Z' just like the 'T' is. 就像“ T”一样，模式末尾的Z需要用“ Z”包裹。 Change "yyyyMMdd'T'HHmmss.SSSZ" to "yyyyMMdd'T'HHmmss.SSS'Z'" and it works. 将"yyyyMMdd'T'HHmmss.SSSZ"更改为"yyyyMMdd'T'HHmmss.SSS'Z'" 。

Removing the Z from the pattern alltogether also led to errors. 从样式中完全删除Z也会导致错误。

Frankly, I'd expect a Java class to have anticipated this. 坦白地说，我希望Java类已经预见到这一点。