C语言一维数组元素左右循环移动代码实现

通过键盘左右方向键控制
VS2012运行如图

// An highlighted block#include<stdlib.h>
#include <stdio.h>
#include <time.h>
#include<conio.h>
void left(int a[],int n)
{int i,k;k = a[0];for (i = 0; i <= n-1-1; i++){a[i] = a[i+1];}a[n-1] = k;
}
void right(int a[],int n)
{int i,k;k = a[n-1];for (i = n-1; i >= 1; i--){a[i] = a[i-1];}a[0] = k;
}
void move_right(int a[],int n,int m)
{int i,k=0;int b[10];for (i = n-m; i <= n-1 ; ++i){b[k] = a[i];k++;}for (i = n-1; i >= m; --i){a[i] = a[i-m];}for (i = 0; i < m; ++i){a[i] = b[i];}
}void move_left(int a[],int n,int m)//m为移动多少个
{int i,j;int b[10];for (i = 0; i < m; ++i){b[i] = a[i];//暂存}for (i = 0; i <= (n-1-m); ++i){a[i] = a[i+m];}for (i = n-m,j=0; i <= n-1;++j, ++i){a[i] = b[j];}
}
void main()
{int i;int a[10];int m = 0;srand((unsigned int)time(NULL));for (i = 0; i < 10; ++i){a[i] = rand()%50+10;printf("%d ",a[i]);}printf("\n");while (1){char ch;ch = getch();switch (ch){case 75://←方向键left(a,10);printf("左移1个：\n");show(a);break;case 77://→方向键right(a,10);printf("右移1个：\n");show(a);break;case 'a':move_left(a,10,2);printf("左移2个：\n");show(a);break;case 'd':move_right(a,10,2);printf("右移2个：\n");show(a);break;}}
}