小时数转成时分秒格式

    public static String getDateByHour(double manHour) {//格式 对于时分秒操作按照
//        int h = min/3600;分钟/3600就是小时
//        int m = (min%3600)/60;
//        int s = (min%3600)%60;//BigDecimal 类操作精准BigDecimal manHourBig = new BigDecimal(manHour);BigDecimal bigDecimal = new BigDecimal(3600);BigDecimal bigDecimalM = new BigDecimal(60);//把小时数换算得到秒-->乘法BigDecimal multiply = manHourBig.multiply(bigDecimal);//得到小时取整-->除法int hh = multiply.divide(bigDecimal, 0, BigDecimal.ROUND_DOWN).intValue();//取模BigDecimal[] results = multiply.divideAndRemainder(bigDecimal);//得到数组中的余数BigDecimal result = results[1];//得到分钟数-->先取模在除算出对应分钟int mm = result.divide(bigDecimalM, 0, BigDecimal.ROUND_DOWN).intValue();//秒-->先取模BigDecimal[] bigDecimals = result.divideAndRemainder(bigDecimal);//数组中的商就是秒int ss = bigDecimals[0].intValue();//拼接为HH:mm:ss格式return hh+":"+mm+":"+ss;}

简单调用

public static void main(String[] args){String dateByHour = getDateByHour(2.5);System.out.println(dateByHour);
}

输出结果

2:30:0

两个时间转成小时数

    public static String getDatePoor(Date nowDate, Date endDate) {long nd = 1000 * 24 * 60 * 60;long nh = 1000 * 60 * 60;long nm = 1000 * 60;long diff = endDate.getTime() - nowDate.getTime();Integer min = Integer.valueOf((int) (diff / nm));if (min <= 0) {return new BigDecimal(0).toString();}BigDecimal bigDecimal = new BigDecimal(min);BigDecimal b = new BigDecimal(60);BigDecimal divide = bigDecimal.divide(b, 2, BigDecimal.ROUND_HALF_UP);return divide.toString();}

简单调用

    public static void main(String[] args) throws ParseException {SimpleDateFormat dateFormat1 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");String datePoor1 = getDatePoor(dateFormat1.parse("2021-10-10 12:00:00" ),dateFormat1.parse("2021-10-10 14:30:00" ));System.out.println(datePoor1+"h");SimpleDateFormat dateFormat2 = new SimpleDateFormat("HH:mm:ss");String datePoor2 = getDatePoor(dateFormat2.parse("12:00:00" ),dateFormat2.parse("14:30:00" ));System.out.println(datePoor2+"h");}

输出结果

2.50h
2.50h